The 1948 United States presidential election in Rhode Island took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.
Rhode Island was won by Democratic candidate, incumbent President Harry S. Truman of Missouri, over the Republican candidate, Governor Thomas E. Dewey of New York. Truman ran with Senator Alben W. Barkley of Kentucky as his running mate, while Dewey ran with Governor Earl Warren of California as his running mate.
Truman won Rhode Island by a margin of 16.15%.
Results
By county County Harry S. TrumanDemocratic Thomas E. DeweyRepublican Various candidatesOther parties Margin Total votes cast # % # % # % # % Bristol 7,562 58.25% 5,343 41.16% 77 0.59% 2,219 17.09% 12,982 Kent 15,287 48.10% 16,299 51.28% 199 0.62% -1,012 -3.18% 31,785 Newport 9,254 45.93% 10,756 53.39% 136 0.68% -1,502 -7.46% 20,146 Providence 149,254 60.73% 93,867 38.20% 2,627 1.07% 55,387 22.53% 245,748 Washington 7,379 43.30% 9,522 55.88% 140 0.82% -2,143 -12.58% 17,041Totals188,73657.59%135,78741.44%3,1790.97%52,94916.15%327,702
Counties that flipped from Democratic to Republican Kent Newport
See also United States presidential elections in Rhode Island
References